The callback function could calculate other properties too, to handle the case where the color is the same, and order by a secondary property as well: list. When we return 1, the function communicates to sort() that the object b takes precedence in sorting over the object a. It is used to add the objects or elements in the array. sort (( a, b ) => (a.color > b.color) ? 1 : - 1 ) On the positive side, though, array literals can replace the need for temporary variables, especially when sending values to a function. The unshift() function is one more built-in array method of JavaScript. You can use the sort() method of Array, which takes a callback function, which takes as parameters 2 objects contained in the array (which we call a and b): list. For example you want to order it by the color name, in alphabetical order: black, red, white. You want to render this list, but first you want to order it by the value of one of the properties. It creates only the variable itself, which can. 1 Using the Spread Operator 2 Using the omEntries () method 3 Using the Object.assign () method 4 Using a For loop 5 Using the Array.forEach () method 6 Final Words Using the Spread Operator You can use the spread operator to create a new object by spreading the elements of the array into an empty object. Say you have an array of objects like this: const list = Declaring a variable of array type does not create an array object or allocate any space for array components. You might have this problem: how do you sort this array of objects by the value of a property? Let's find out how to sort an array of objects by a property value in JavaScript!
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